如何用C语言写一个2048游戏?

写一个2048游戏,需要掌握C语言的基础知识,了解游戏规则。以下是2048游戏的C语言简化版:

cCopy code # include & ltstdio.h & gt# include & ltstdlib.h & gt# include & lttime.h & gt# include & ltconio.h & gt#定义SIZE 4int矩阵[SIZE][SIZE];void init _ matrix(){ for(int I = 0;我& lt尺寸;i++){ for(int j = 0;j & lt尺寸;j++) {

矩阵[I][j]= 0;

}

}

} void add _ random _ tile(){ int empty _ tiles[SIZE * SIZE][2];int empty _ count = 0;for(int I = 0;我& lt尺寸;i++){ for(int j = 0;j & lt尺寸;j++) { if (matrix[i][j] == 0) {

empty _ tiles[empty _ count][0]= I;

empty _ tiles[empty _ count][1]= j;

empty _ count++;

}

}

} if(empty _ count = = 0){ return;

} int索引= rand()% empty _ count;int value =(rand()% 2+1)* 2;

matrix[empty _ tiles[index][0]][empty _ tiles[index][1]]= value;

} void print _ matrix(){ for(int I = 0;我& lt尺寸;i++){ for(int j = 0;j & lt尺寸;j++) { printf("%5d ",matrix[I][j]);

} printf(" \ n ");

}

}int move(int dx,int dy){ int moved = 0;如果(dx!= 0){ for(int y = 0;y & lt尺寸;y++){ int last _ non _ empty = dx & gt;0 ?SIZE-1:0;for(int x = dx & gt;0 ?SIZE-1:0;x & gt= 0 & amp& ampx & lt尺寸;x-= dx){ if(matrix[y][x]= 0){ continue;

} if(matrix[y][last _ non _ empty]= = 0){

矩阵[y][last_non_empty] =矩阵[y][x];

matrix[y][x]= 0;

moved = 1;

} else if(matrix[y][last _ non _ empty]= = matrix[y][x]){

matrix[y][last _ non _ empty]* = 2;

matrix[y][x]= 0;

last _ non _ empty-= dx;

moved = 1;

} else if (last_non_empty - dx!= x) {

矩阵[y][last_non_empty - dx] =矩阵[y][x];

matrix[y][x]= 0;

last _ non _ empty-= dx;

moved = 1;

}否则{

last _ non _ empty-= dx;

}

}

}

} else { for(int x = 0;x & lt尺寸;x++){ int last _ non _ empty = dy & gt;0 ?SIZE-1:0;for(int y = dy & gt;0 ?SIZE-1:0;y & gt= 0 & amp& ampy & lt尺寸;y-= dy){ if(matrix[y][x]= 0){ continue;

} if(matrix[last _ non _ empty][x]= = 0){

矩阵[last_non_empty][x] =矩阵[y][x];

矩阵[y][x